Linux下如何获取cpu的利用率

fclose(fd); //封闭文件fd

}

int cal_cpuoccupy (CPU_OCCUPY *o, CPU_OCCUPY *n)

{

unsigned long od, nd;

unsigned long id, sd;

int cpu_use = 0;

od = (unsigned long) (o->user + o->nice + o->system +o->idle);//第一次(用户+优先级+体系+余暇)的时光再赋给od

nd = (unsigned long) (n->user + n->nice + n->system +n->idle);//第二次(用户+优先级+体系+余暇)的时光再赋给od

id = (unsigned long) (n->user - o->user); //用户第一次和第二次的时光之差再赋给id

sd = (unsigned long) (n->system - o->system);//体系第一次和第二次的时光之差再赋给sd

if((nd-od) != 0)

cpu_use = (int)((sd+id)*10000)/(nd-od); //((用户+体系)乖100)除(第一次和第二次的时光差)再赋给g_cpu_used

else cpu_use = 0;

//printf("cpu: %u/n",cpu_use);

return cpu_use;

}

get_cpuoccupy (CPU_OCCUPY *cpust) //对无类型get函数含有一个形参构造体类弄的指针O

{

FILE *fd;

int n;

char buff[256];

CPU_OCCUPY *cpu_occupy;

cpu_occupy=cpust;

fd = fopen ("/proc/stat", "r");

fgets (buff, sizeof(buff), fd);

sscanf (buff, "%s %u %u %u %u", cpu_occupy->name, &cpu_occupy->user

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